The three vectors 
, 
, and 
each terminate on the plane. We can get two vectors that lie on the plane itself (or rather, point in the same direction as vectors that do lie on the plane) by taking the vector difference of any two of these. For instance,
Then the cross product of these two results is normal to the plane:
Let 
be a point on the plane. Then the vector connecting to a known point on the plane, say (0, 0, 1), is orthogonal to the normal vector above, so that
which reduces to the equation of the plane,
Let 
. Then the volume of the region above 
and below the plane is
It's a simultaneous equation:
Steps:
1.Number the equations..
a+b=77 -1
a-b=13 -2
2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together
a + b = 77
+ + +
a (-b) = 13
Which gives;
2a = 90
Then solve to find a:
2a=90
a= 90/2
a=45
3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.
a + b = 77
(45) + b = 77
b=77-45
b=32
4.Solution
a=45
b=32
Answer:
320 sq in
Step-by-step explanation:
4(1/2*8*16) + (8*8)
= 4(64) + (64)
= 5(64)
= 320
1 is L
2 is N
3 is M
Look back at your notes if you have any.
<span> Congruent </span><span>figures. Hope that helped. </span>
