The value of the quantity after 1 year, to the nearest hundredth is 4000.00
<h3>The exponential form of an equation</h3>
The standard exponential equation is eexpressed as:
![P(t)=P_0e^{kt}](https://tex.z-dn.net/?f=P%28t%29%3DP_0e%5E%7Bkt%7D)
Given the following parameters
![P_0=4000\\r =0.0005\\t = \frac{1}{50} =0.02 (yearly)](https://tex.z-dn.net/?f=P_0%3D4000%5C%5Cr%20%3D0.0005%5C%5Ct%20%3D%20%5Cfrac%7B1%7D%7B50%7D%20%3D0.02%20%28yearly%29)
Substitute into the formula to have:
![P(t)=4000e^{0.0005(0.02)}\\P(1)=4000e^{0.00001}\\P(1)=4000](https://tex.z-dn.net/?f=P%28t%29%3D4000e%5E%7B0.0005%280.02%29%7D%5C%5CP%281%29%3D4000e%5E%7B0.00001%7D%5C%5CP%281%29%3D4000)
Hence the value of the quantity after 1 year, to the nearest hundredth is 4000.00
Learn more on exponential equations here: brainly.com/question/12940982
Answer:
The area of the sector is ![12.8\pi\ units^2](https://tex.z-dn.net/?f=12.8%5Cpi%5C%20units%5E2)
Step-by-step explanation:
we know that
The area of a complete circle (16π units^2) subtends a central angle of 2π radians
so
using proportion
Find out the area of a sector , if the central angle is equal to 8π/5 radians
![\frac{16\pi}{2\pi}=\frac{x}{(8\pi/5)}\\\\x=8(8\pi/5)\\\\x= 12.8\pi\ units^2](https://tex.z-dn.net/?f=%5Cfrac%7B16%5Cpi%7D%7B2%5Cpi%7D%3D%5Cfrac%7Bx%7D%7B%288%5Cpi%2F5%29%7D%5C%5C%5C%5Cx%3D8%288%5Cpi%2F5%29%5C%5C%5C%5Cx%3D%2012.8%5Cpi%5C%20units%5E2)
I don't know what is the correct answer
6m-1
You have to multiply 6x2=12
12 subtract by 1 is 11
Have a nice day!