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mezya [45]
3 years ago
13

The perimeter of a building is 78 feet. The width of the building is seven more than three times the length of the building. Wha

t is the width of the building? Solve algebraically Justify your answer using math vocabulary. MUST USE COMPLETE SENTENCES​
Mathematics
1 answer:
Alchen [17]3 years ago
8 0

P=2l+2w

W=7+3l

So substitute into the original equation

P=2l + 2(7+3l)

78=2l +14 + 6l

-14 -14

—————-

64=8l

8=length

W=7+3l

= 7+3(8)

=7+24

=31

Check your work

Perimeter=8+8+31+31

=78

Hope this helps

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Viefleur [7K]
The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.

We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.

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