3 years ago

apples cost 3x. Oranges cost (x+6). which expression represents the cost to buy one apple and five oranges?

Mathematics

2 answers:

Alexeev081 [22]3 years ago

3 0

3(1)+((5+6))

3+11

14 i think

BARSIC [14]3 years ago

3 0

1 apple * cost + 5 oranges* cost

1* 3x+ 5* (x+6)

distribute

3x +5x+30

combine like terms

8x+30

You might be interested in

a car show is selling tickets to rise money. adult tickets sell for $5.00 and children under 12 cost $2.00. you need to raise mo

OlgaM077 [116]

Let c = number of children
Let a = number of adults

5a + 2c > 3350

3 0

3 years ago

The area of a rectangle is at least 115 square centimeters. The width of the rectangle is 5 centimeters and the length of the re

Natali [406]

The census is 60 because it’s obviously when you divided

3 0

3 years ago

How many nanoseconds does it take for a computer to perform one calculation if it performs calculations per second?

igor_vitrenko [27]

I believe the correct question is:

6.7*10^7 calc/sec?

So:

1/(6.7 x 10^7) = seconds per calculation

1/(6.7 x 10^7) = 100/(6.7 x 10^9) = 14.9 x 10^-9 seconds per calculation = 14.9 ns

Which is approximately 15 ns

Answer:

15 ns

7 0

3 years ago

A certain calling card gives you the following rate to call Malaysia. There is a connection fee of $0.39 which allows you to con

Paha777 [63]

F(x<40)= 0.39+(x*0.24) This formula will quantify what you have written out above.

4 0

3 years ago

Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.

madreJ [45]

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

$\Rightarrow ^2C_1$

Total no of ways of choosing a marble from bag-I

$\Rightarrow ^{10}C_1$

No of ways of choosing a blue marble from bag-II

$\Rightarrow ^{10}C_1$

Total no of ways of choosing a marble from bag-II

$\Rightarrow ^{20}C_1$

The probability that he will pull out a blue marble from each bag is

$\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}$

$\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}$

3 0

3 years ago