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horrorfan [7]
3 years ago
13

Plz help i really do need help

Mathematics
1 answer:
Maslowich3 years ago
6 0

Answer:

it just says PDF won't let me download I. sorry

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Lucy's school is celebrating easter by having a race in which the winner will get a basket of chocolate eggs. lucy is the fiftie
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The question also states that Lucy has a winning probability of 1/50, which means that she has 1 chance of winning if the total runners were 50. Therefore, there are 49 runners who may be faster than her.

The fact that Lucy is the 50th slowest runner, means that starting from the slowest she is in 50th position, therefore there are 49 runners that are slower than her.

The total number of runners will be the sum of those faster than Lucy, those slower than Lucy and Lucy:
49 + 49 + 1 = 99

There are 99 runners in Lucy's school.
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The value of 3 in 6,300 is 10 times the value of 3 in 530. And your welcome.
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Principal, $2000; Annual interest rate, 5.3%; time, 2 years<br> After 2 years?
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Step-by-step explanation:

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3 years ago
NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)
olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level       PA (men)      PA (Women)

Sedentary              1.00                1.00

    Low                    1.11                1.12

  Active                   1.25                1.27

Very Active              1.48                1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

        = 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0
3 years ago
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