-10v^9+8v^6+2v^5
10=5*2
8=2^3
2=2
The common factor is 2 and its least exponent is 1
The least exponent for the variable v is 5
Then, the GFC of the polynomial is 2v^5
Factoring:
2v^5 [ -(10v^9)/(2v^5)+(8v^6)/(2v^5)+(2v^5)/(2v^5) ] =
2v^5 (-5v^(9-5)+4v^(6-5)+1) =
2v^5 (-5v^4+4v+1)
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
<h3>How to analyze quadratic equations</h3>
In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:
g(x) = C · (x - h)² - k (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.
x = 2
g(2) = (2 - 5)² + 1
g(2) = 10
x = 8
g(8) = (8 - 5)² + 1
g(8) = 10
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
To learn more on parabolae: brainly.com/question/21685473
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I want to help you but please make it easier to understand
Answer:
3: 97
10: 97
9: 83
5: 97
7: 83
16: 97
Im 100% on these answers bc Ive already taken this class :)