Please help with any you can, i will give brainliest.
1 answer:
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Answer:
21 students pass
Step-by-step explanation:
Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction (which is 75% represented as a fraction).
The fraction can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with
.
Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.
The denominators cancel out leaving you with a simple equation to simplify.
Finally, divide both sides by four in order to isolate the variable.
X = 21.
Given function is
now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into
so RHD=
Now set both equal
k=-0.47
<u>Hence final answer is -0.47.</u>