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Tom [10]
3 years ago
8

Identify the mode: 59, 46, 42, 54, 63, 63, 71, 39, 51, 49, 72, 77, 61,53

Mathematics
2 answers:
Naddika [18.5K]3 years ago
5 0

Answer:

63

Step-by-step explanation:

63 is repeated the most

Ivanshal [37]3 years ago
4 0

Answer:

63

Step-by-step explanation:

The mode is the element that occurs most in the data set.

<em>good luck, i hope this helps :)</em>

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I just need some help solving this question, i’m not sure what to do
KonstantinChe [14]

From the double-angle identity,

cos2x=2*sinx*cosx

we can rewritte our given equation as:

4sinxcosx-2cosx=0

By factoring 2cosx on the left hand side, we have

2cosx(2sinx-1)=0

This equation has 2 solutions when

\begin{gathered} cosx=0\text{ ...\lparen A\rparen} \\ and \\ 2sinx-1=0\text{ ...\lparen B\rparen} \end{gathered}

From equation (A), we obtain

x=\frac{\pi}{2}\text{ or }\frac{3\pi}{2}

and from equation (B), we have

\begin{gathered} sinx=\frac{1}{2} \\ which\text{ gives} \\ x=\frac{\pi}{6}\text{ or }\frac{5\pi}{6} \end{gathered}

On the other hand, we can find one more solution from the original equation by substituting x=0, that is,

\begin{gathered} 2ccos(2\times0)-2cos0=0 \\ which\text{ gives} \\ 2\times1-2\times1=0 \\ so\text{ 0=0} \end{gathered}

then, x=0 is another solution. In summary, we have obtained the following solutions:

\begin{gathered} x=0 \\ x=\frac{\pi}{2}\text{or}\frac{3\pi}{2}\text{ and } \\ x=\frac{\pi}{6}\text{or}\frac{5\pi}{6} \end{gathered}

However, the intersection of the last set is empty. So the unique solution is x=0 as we can corroborate on the following picture:

Therefore, the solution set is: {0}

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1 year ago
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One may note, you didn't really include any "of the folllowing" ones

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solve for "x"
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Answer:

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Step-by-step explanation:

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