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dolphi86 [110]
3 years ago
10

Evaluate x2 + 14 for x = –5.

Mathematics
2 answers:
OlgaM077 [116]3 years ago
6 0

Answer:

x2+14 x=-5

-5(2)+14

-10+14=4

Scorpion4ik [409]3 years ago
4 0

Answer:

39

Step-by-step explanation:

x² + 14 ← substitute x = - 5

= (- 5)² + 14

= 25 + 14

= 39

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(-4,2)

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3 years ago
Team A scored three times as many points as Team B. Which team scored most points? If Team A scored n point, how many points did
jonny [76]

Answer:

They scored 66 points

Step-by-step explanation:

Sally scored 45% out of the 100%

And there are 120 points in all.

To find the rest of the teams points you have to subtract Sally's points:

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So to find this out you solve for x (points):

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Step-by-step explanation:

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2 years ago
To estimate the mean height μ of male students on your campus, you will measure an SRS of students. You know from government dat
denis-greek [22]

Answer:

a) The standard deviation of x must be 0.25 inches.

b) We need a sample of 125 to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a).

Step-by-step explanation:

The 68-95-99.7 states that:

68% percent of the measures of a normally distributed sample are within 1 standard deviation of the mean.

95% percent of the measures of a normally distributed sample are within 2 standard deviations of the mean.

99.7% percent of the measures of a normally distributed sample are within 3 standard deviations of the mean.

The standard deviation of the population is 2.8. This means that \sigma = 2.8.

(a) What standard deviation must x⎯⎯⎯ have so that 95% of all samples give an x⎯⎯⎯ within one-half inch of μ?

We want to have a sample in which 2 standard deviations are within 0.5 inches of the mean.

So, the standard deviation of the sample must be:

2s = 0.5

s = 0.25

The standard deviation of x must be 0.25 inches.

(b) How large an SRS do you need to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a)?

We have that the standard deviation of a sample of length n is given by the following formula:

s = \frac{\sigma}{\sqrt{n}}.

We want s = 0.25 and we have \sigma = 2.8. So

0.25 = \frac{2.8}{\sqrt{n}}

0.25\sqrt{n} = 2.8

\sqrt{n} = 11.2

\sqrt{n}^{2} = (11.2)^{2}

n = 125.44

We need a sample of 125 to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a).

8 0
4 years ago
What is 1.25 in standard form?
Irina-Kira [14]
I’m not sure but I think it’s 1.25 x 10^0
3 0
3 years ago
Read 2 more answers
Estimate square root of21
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Square root of 21 is 

<span>4.58257569496
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I rounded it to 4.58

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3 years ago
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