Answer:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

Step-by-step explanation:
For this case we have the following distribution given:
X 0 1 2 3 4 5 6
P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02
For this case we need to find first the expected value given by:

And replacing we got:

Now we can find the second moment given by:

And replacing we got:

And the variance would be given by:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

It is false because 0and 2 and the middle number will be 1
Total charges from bank A exists $15.
Total charges on Bank B spending exists $45.
<h3>How to estimate the
Total charges on bank B?</h3>
Given: Bank A charges a $15 monthly fee for a checking account and debit card, with unlimited transactions.
Shade 25 transactions.
Total charges from bank A = $15 monthly
Bank B charged a $35 monthly fee for a checking account and debit card, plus $ 0.70 for each transaction.
She made 25 transactions.
Total charges on bank B = $35 + (0.40)25
Total charges on bank B = $35+10
Total charges on bank B = $45
To learn more about Total charges on the bank refer to:
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Answer:
8/35,9/35
Step-by-step explanation:
L.C.M. of 5 and 7=5×7=35
1/5×7/7=7/35
2/7×5/5=10/35
numbers between 7/35 and 10/35 are 8/35,9/35
actually there are infinite numbers
like 71/350,72/350,73/350,...