The lateral area is 1560 cm².
The lateral area is the area of the lateral faces (the faces that are not bases). The dimensions of these are:
24 by 26
10 by 26
26 by 26
These are all rectangles. The area of each rectangle is given by length * width:
24*26 = 624
10*26 = 260
26*26 =676
624+260+676=1560
Answer:
![\text{c) }\sqrt[4]{64}=2\sqrt[4]{4}](https://tex.z-dn.net/?f=%5Ctext%7Bc%29%20%7D%5Csqrt%5B4%5D%7B64%7D%3D2%5Csqrt%5B4%5D%7B4%7D)
Step-by-step explanation:
![\text{a) }64\qquad\text{an integer; not a surd}\\\\\text{b) }\sqrt[6]{64}=2\qquad\text{an integer; not a surd}\\\\\text{c) }\sqrt[4]{64}=2\sqrt[4]{4}\qquad\textbf{a surd}\\\\\text{d) }\sqrt[3]{64}=4\qquad\text{an integer; not a surd}](https://tex.z-dn.net/?f=%5Ctext%7Ba%29%20%7D64%5Cqquad%5Ctext%7Ban%20integer%3B%20not%20a%20surd%7D%5C%5C%5C%5C%5Ctext%7Bb%29%20%7D%5Csqrt%5B6%5D%7B64%7D%3D2%5Cqquad%5Ctext%7Ban%20integer%3B%20not%20a%20surd%7D%5C%5C%5C%5C%5Ctext%7Bc%29%20%7D%5Csqrt%5B4%5D%7B64%7D%3D2%5Csqrt%5B4%5D%7B4%7D%5Cqquad%5Ctextbf%7Ba%20surd%7D%5C%5C%5C%5C%5Ctext%7Bd%29%20%7D%5Csqrt%5B3%5D%7B64%7D%3D4%5Cqquad%5Ctext%7Ban%20integer%3B%20not%20a%20surd%7D)
Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.

To find:
The theorem which shows that
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer:
Option A is correct that is 
Step-by-step explanation:
We have been given a formula 

We will put values of n in
when n=2 we get
when n=3
Therefore, Option A is correct that is 
Answer:
x=10
Step-by-step explanation:
hope this helps