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sammy [17]
3 years ago
5

Please i need help:/

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

the answer would be B or 358.38

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a recipe called for the ratio of sugar to flour to be 5 to 1 if you use 35 ounces of sugar how many ounces of flour do you need
den301095 [7]
7

The answer is 7 
The ratio would look like 35/7
4 0
3 years ago
What is 0.28 and 2.65 as a fraction in simplest form? explain
Oksanka [162]
28/100=14/50=7/25 &the second one 2=200/100 so 200/100+65/100=265/100

265/100=53/20
5 0
3 years ago
Read 2 more answers
30 POINTS NO CAP PLEASE HELP ME NEED RIGHT ANSWER<br> 2 different question
adoni [48]

Answer:

1. 3/2

Domain =

-3, -2, 1, 4

Range =

-4, -2, 0, 3, 5

no it is not a function

Step-by-step explanation:

3 0
3 years ago
Help needed on this composition math problem
Marrrta [24]

Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of <em>function</em> operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the <em>resulting</em> function is any <em>real</em> number except x = 1/3.

<h3>How to analyze a composed function</h3>

Let be f and g functions. Composition is a <em>binary function</em> operation where the <em>variable</em> of the <em>former</em> function (f) is substituted by the <em>latter</em> function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the <em>composed</em> function is:

f\,\circ\,g \,(x) = \frac{\frac{1}{x} }{\frac{1}{x}-3}

f\,\circ\,g\,(x) = \frac{\frac{1}{x} }{\frac{1-3\cdot x}{x} }

f\,\circ\,g\,(x) = \frac{1}{1-3\cdot x}

The domain of the function is the set of x-values such that f ° g (x) exists. In the case of <em>rational</em> functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is \mathbb{R} - \{\frac{1}{3} \}.

To learn more on composed functions: brainly.com/question/12158468

#SPJ1

3 0
1 year ago
I want a way to solve this question​
AURORKA [14]

Answer:

d

Step-by-step explanation:

Using the Cosine rule to find ∠ A

cosA = \frac{b^2+c^2-a^2}{2bc}

         = \frac{5.1^2+5.7^2-7.3^2}{2(5.1)(5.7)}

         = \frac{26.01+32.49-53.29}{58.14}

         = \frac{5.21}{58.14} , then

∠ A = cos^{-1} ( \frac{5.21}{58.14} ) ≈ 84.9° ( to 1 dec. place )

5 0
2 years ago
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