Step One
Begin by drawing a line parallel to the x axis. Create it so it goes through (0,1)
This line you have drawn should hit points on the figure at (-5,1) (-2,1) and (3,1)
You now have a figure on the bottom that is a trapezoid. It has 2 small triangles on top of it. We'll talk about them later.
Step Two
Find the area of the trapezoid.
<em>Formula</em>
Area = (b1 + b2)*h/2
h = 1 - - 3 = 4
b1 = 3 - - 8 = 11
b2 = 3 - - 5 = 8
Area = (11 + 8)*4 / 2
Area = (19 ) * 2
Area = 38
Step Three
Find the area of the small triangle on the left.
The base goes from -5 to - 2 which is 3 units.
The height goes from 1 to 3 (using the y axis as a reference) which is 2
Area = 1/2 * b * h
Area = 1/2 *3 * 2
Area = 3
Step Four
Find the area of the small triangle on the right.
The base is 5 (see if you can get 5 as an answer)
The height is 1.
Area = 1/2 b * h
Area = 1/2 5 * 1
Area = 2.5
Step Five
Total Area is found by adding the three areas together.
Total Area = trapezoid + small triangle on the left + small triangle on the right
Total Area = 38 + 3 + 2.5 = 43.5
43.5 <<<< answer
Answer:
Bottom left.
Step-by-step explanation:
You can try plugging in points as well but that graph is the general shape of x^3, just compressed by 1/3.
Answer:
(-2,7) those are the coordinate. in which he will land
Answer:
14, sqrt(200), 15
Step-by-step explanation:
14 is the least sqrt(200) equals 14.14 then 15
Answer:
x^2-2x-13
Step-by-step explanation:
f(x) = 2x-5
g(x) = x^2 -4x-8
f(x) +g(x) = 2x-5 + x^2 -4x-8
Combine like terms
= x^2+2x-4x-5-8
=x^2-2x-13
