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GalinKa [24]
3 years ago
8

The blue are the two boards that you need to use.

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Answer:

for what?

Step-by-step explanation:

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Please help me with this .
Flauer [41]

Answer:

with what

Step-by-step explanation:

can you please post the picture

look at the picture to see how to add a pic to a question

7 0
2 years ago
Help. What’s the correct answer?
vesna_86 [32]

Answer:

f(g(x)) = -9(sqrt(x + 1) ) + 9

-36

Step-by-step explanation:

This is easier to see if you use the expanded notation.

f(g(x)) = ?

But what that means is that the left most function is f(x) and where every you see an x, you put in a g(x) like so

f(g(x)) = -9(g(x)) + 9    Now substitute the right side of g(x) into the equation for f(x)

f(g(x)) = -9(sqrt(x + 1) ) + 9

Edit to get the numerical answer.

This should be your answer or the expression that will give you the answer.

f(g(24)) = -9(sqrt(24+1) ) + 9

f(g(24)) = -9sqrt(25) +9

f(g(24)) = -  9*5 + 9

f(g(24)) = - 45 + 9

f(g(24)) = - 36

7 0
3 years ago
Read 2 more answers
you build four scale models of the Empire State Building. The smallest model is 3 centimeters tall. The height of each model is
WARRIOR [948]
The answer would be 3^4 =  81
4 0
3 years ago
Read 2 more answers
Intersection point of Y=logx and y=1/2log(x+1)
GalinKa [24]

Answer:

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

The Problem:

What is the intersection point of y=\log(x) and y=\frac{1}{2}\log(x+1)?

Step-by-step explanation:

To find the intersection of y=\log(x) and y=\frac{1}{2}\log(x+1), we will need to find when they have a common point; when their x and y are the same.

Let's start with setting the y's equal to find those x's for which the y's are the same.

\log(x)=\frac{1}{2}\log(x+1)

By power rule:

\log(x)=\log((x+1)^\frac{1}{2})

Since \log(u)=\log(v) implies u=v:

x=(x+1)^\frac{1}{2}

Squaring both sides to get rid of the fraction exponent:

x^2=x+1

This is a quadratic equation.

Subtract (x+1) on both sides:

x^2-(x+1)=0

x^2-x-1=0

Comparing this to ax^2+bx+c=0 we see the following:

a=1

b=-1

c=-1

Let's plug them into the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}

x=\frac{1 \pm \sqrt{1+4}}{2}

x=\frac{1 \pm \sqrt{5}}{2}

So we have the solutions to the quadratic equation are:

x=\frac{1+\sqrt{5}}{2} or x=\frac{1-\sqrt{5}}{2}.

The second solution definitely gives at least one of the logarithm equation problems.

Example: \log(x) has problems when x \le 0 and so the second solution is a problem.

So the x where the equations intersect is at x=\frac{1+\sqrt{5}}{2}.

Let's find the y-coordinate.

You may use either equation.

I choose y=\log(x).

y=\log(\frac{1+\sqrt{5}}{2})

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

6 0
3 years ago
Points H and F lie on circle c What is the length of line segment GH?
Nina [5.8K]

Answer:

6 units

Step-by-step explanation:

Given: Points H and F lie on  circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.

To find: Length of GH.

Sol: EC = CH = 9 (Radius of the same circle are equal)

Now, GC = GH + CH

GC = GH + 9

Now In ΔEGC, using pythagoras theorem,

(Hypotenuse)^{2} = (Base)^{2} +(Altitude)^{2} ......(ΔEGC is a right triangle)

(GC)^{2} = (GE)^{2} +(EC)^{2}

(GH + 9)^{2} = (9)^{2} +(12)^{2}

(GH )^{2} + (9)^{2} + 18GH = 81 + 144

(GH )^{2} + 81 + 18GH = 81 + 144

(GH )^{2} + 18GH = 144

Now, Let GH = <em>x</em>

x^{2} +18x = 144

On rearranging,

x^{2} +18 x - 144 = 0

x^{2} - 6x +24x + 144 = 0

x (x-6) + 24 (x - 6) =0

(x - 6) (x + 24) = 0

So x = 6  and x = - 24

∵ x cannot be - 24 as it will not satisfy the property of right triangle.

Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.

3 0
3 years ago
Read 2 more answers
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