Question

A person is using a new tennis ball launching machine that is 15 inches by 15 inches by 14. Assuming the machine uses tennis balls that are spherical and 2.7 inches in diameter, how many tennis should fit in one of the top of the machine.

Answer 1

Answer:

305 tennis balls should fit

Step-by-step explanation:

The volume of the machine is length * width * height

So Volume of Machine = 15 * 15 * 14 = 3150

Volume of Sphere is  $V=\frac{4}{3}\pi r^3$

Where

V is volume and r is radius (half of diameter)

Since 2.7 is diameter, 2.7/2 = 1.35 inches is radius

Volume of 1 tennis ball = $V=\frac{4}{3}\pi r^3\\V=\frac{4}{3}\pi (1.35)^3\\V=10.3$ (rounded to 1 decimal)

We simply divide the volume of the machine by volume of 1 tennis ball to get number of tennis balls:

3150/10.3 = 305.82

the fractional amount (.82) won't be possible so the max number of balls possible is 305 balls