You have to make the mixed number into a fraction in order to divide
well, let's check the graph, and use two points off of it..hmmmm it passes through (4, 0) and it also passes through (0, -4).
so, what would be the equation of a line that passes through those two points?
keeping in mind that
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) ~\hfill slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-4-0}{0-4}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=1(x-4)\implies y=x-4 \\\\\\ -x+y=-4\implies \stackrel{\textit{standard form}}{x-y=4}\\\hspace{34em}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B4%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B0%7D~%2C~%5Cstackrel%7By_2%7D%7B-4%7D%29%20~%5Chfill%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B-4-0%7D%7B0-4%7D%5Cimplies%201%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-0%3D1%28x-4%29%5Cimplies%20y%3Dx-4%20%5C%5C%5C%5C%5C%5C%20-x%2By%3D-4%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7Bx-y%3D4%7D%5C%5C%5Chspace%7B34em%7D)
Answer: Yes, it's true.
Step-by-step explanation:
The first step is to convert the mixed number
to a fraction. The procedure for this is:
- Multiply the whole number 1 by the denominator 5.
- Add the product obtained and the numerator 2 (This will be the numerator of the fraction).
- The denominator does not change. It will be 5.
Then:
![1\frac{2}{5}=\frac{(1)(5)+2}{5}=\frac{7}{5}](https://tex.z-dn.net/?f=1%5Cfrac%7B2%7D%7B5%7D%3D%5Cfrac%7B%281%29%285%29%2B2%7D%7B5%7D%3D%5Cfrac%7B7%7D%7B5%7D)
Rewrite the equation:
Notice that the denominators on the left side are 4 and 5 and the denominator on the right side are also 4 and 5.
Then, the Least Common Denominator (LCD) on both sides is:
![LCD=5*2^2=20](https://tex.z-dn.net/?f=LCD%3D5%2A2%5E2%3D20)
Now we can solve the subtraction on the left side of the equation and the addition on the righ side:
![\frac{(7*4)-(3*5)}{20}=\frac{(1*5)+(2*4)}{20}\\\\\frac{13}{20}=\frac{13}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B%287%2A4%29-%283%2A5%29%7D%7B20%7D%3D%5Cfrac%7B%281%2A5%29%2B%282%2A4%29%7D%7B20%7D%5C%5C%5C%5C%5Cfrac%7B13%7D%7B20%7D%3D%5Cfrac%7B13%7D%7B20%7D)
Therefore:
(IT'S TRUE)
The critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881
<h3>How to determine the critical values corresponding to a 0.01 significance level?</h3>
The scatter plot of the election is added as an attachment
From the scatter plot, we have the following highlights
- Number of paired observations, n = 8
- Significance level = 0.01
Start by calculating the degrees of freedom (df) using
df =n - 2
Substitute the known values in the above equation
df = 8 - 2
Evaluate the difference
df = 6
Using the critical value table;
At a degree of freedom of 6 and significance level of 0.01, the critical value is
z = 0.834
From the list of given options, 0.834 is between -0.881 and 0.881
Hence, the critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881
Read more about null hypothesis at
brainly.com/question/14016208
#SPJ1