Select the table representing a linear function. (Graph them if necessary.)

Car insurance of 800 Is twice what it was a decade ago. Find the cost of the insurance then

mr Goodwill [35]

Answer:

it was 400 back then, a decade ago

Step-by-step explanation:

6 0

3 years ago

If a coin is tossed and a number cube is rolled what is the probability of getting heads and the number cube shows 3?

Maurinko [17]

Answer:

1/12

Step-by-step explanation:

Since the probability of getting heads is 1/2 and the probability of the number cube getting three is 1/6, we multiply.

For every coin flip, there is a 1/6 chance of getting a three. But since there is another condition, we have to multiply. Multiplying both fractions make 1/12.

4 0

2 years ago

What is the answer

Molodets [167]

Answer:

the y axis is the answer

4 0

3 years ago

The height of a punted football can be modeled with the quadratic function 0.01x^2 + 1.18x+2.

Fantom [35]

The function of the path of the punted ball is a quadratic function which

follows the path of a parabola.

The correct responses are;

Part A: The coordinates of the vertex is $\underline {(59, \, 36.81)}$

Part B: The maximum height of the punt is 36.81 ft.

Part C: The defensive player must reach up to 7.65 feet to block the punt.

Part D: The distance down the field the ball will go without being blocked is approximately 119.67 ft.

Reasons:

The function for the height of the punted ball is; h = -0.01·x² + 1.18·x + 2

Assumption; The distances are feet.

Part A: By completing the square, we have;

f(x) = -0.01·x² + 1.18·x + 2

100·f(x) = -x² + 118·x + 200

-100·f(x) = x² - 118·x - 200

x² - 118·x + (118/2)²= 200 + (118/2)²

(x - 59)² = 200 + (59)² = 3681

(x - 59)² - 3681

At the vertex, -3281 = -100·f(x)

∴ f(x) at the vertex = -3681/-100 = 36.81

$\mathrm{\underline{Coordinate \ of \ the \ vertex = (59, \, 36.81)}}$

Part B: The maximum height is given by the y-value at the vertex = 36.81 ft.

Part C: When x = 5, we have;

h = -0.01·x² + 1.18·x + 2

h = -0.01 × 5² + 1.18 × 5 + 2 = 7.65

The defensive player must reach up to 7.65 feet to block the punt

Part D: The distance the ball will go before it hits the ground is given by

the function, for the height as follows;

h = -0.01·x² + 1.18·x + 2 = 0

From the completing the square method, above, we get;

-0.01·x² + 1.18·x + 2 = 0

x² - 118·x - 200 = 0

x² - 118·x + (118/2)²= 200 + (118/2)²

x² - 118·x + (59)²= 200 + (59)² = 3681

(x - 59)² = 3681

x - 59 = ±√3681

x = 59 ± √3681

x = 59 + √3681 ≈ 119.67

The distance down the field the ball will go without being blocked, x ≈ 119.67 ft.

Learn more here:

brainly.com/question/24136952

5 0

2 years ago

After obtaining a warrant, the police attached GPS tracking device to the car of a murder suspect. Suppose the car was located a

AURORKA [14]

Answer:

Part a) The coordinates of the suspect's car at its final destination are (4,4)

Part b) The distance traveled by the suspect was 10 miles

Part c) $d=5.66\ mi$

Step-by-step explanation:

The correct question in the attached figure

Part a) What are the coordinates of the suspect's car at its final destination?

we know that

The original position is the origin of a Cartesian coordinate system (0,0)

1) The suspect's car was tracked going 5 mi due east

That means----> 5 mi at right

the new coordinates are (5,0)

2) The suspect's car was tracked going 4 mi due north

That means----> 4 mi up

the new coordinates are (5,4)

3) The suspect's car was tracked going 1 mi due west

That means----> 1 mi at left

the new coordinates are (4,4)

therefore

The coordinates of the suspect's car at its final destination are (4,4)

Part b) What was the distance traveled by the suspect?

The distance traveled is

5 mi due east + 4 mi due north + 1 mi due west

$5+4+1=10\ mi$

therefore

The distance traveled by the suspect was 10 miles

Part c) What is the distance as the crow flies between the original position and the final position of the suspect's car?

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Remember that

The original position was (0,0) and the final position was (4,4)

substitute in the formula

$d=\sqrt{(4-0)^{2}+(4-0)^{2}}$

$d=\sqrt{(4)^{2}+(4)^{2}}$

$d=\sqrt{32}\ mi$

$d=5.66\ mi$

5 0

2 years ago