Question

Given the arithmetic series:2+4+6....Find the sum of 41st term to 47th term ​

Answer 1

Answer:

Step-by-step explanation:

To find the 41st term to 47th term, we must find the equation of how to get those terms.

The equation for arithmetic terms is $a_{n} =a_{1} + (n-1)d$, where d is the difference between two side-by-side terms.

By using this equation format, we get the equation $a_{n} =2+ (n-1)2 = 2n$

That means the terms are

$a_{41} =2*41 = 82\\a_{42}=2*42 = 84\\a_{43} = 2*43 = 86\\a_{44} = 2*44 = 88\\a_{45} = 2*45 = 90\\a_{46}=2*46 = 92\\a_{47} = 2*47 = 94$

Now to find the sum, we just add all the terms up simply

Sum = 82 + 84 +86 + 88 + 90 + 92 +94 = 616

Hope that helps!