In the circle below, Ab and CD are chords intersecting at E if AE=5, BE,12, and CE=6, what is the length of DE
1 answer:
Answer:
DE = 10
Step-by-step explanation:
Here, we want to find the value of DE
we use the intersecting chord principle
That will be;
CE * ED = AE * BE
we have;
6 * DE = 5 * 12
DE = (5 * 12)/6
DE = 5 * 2
DE = 10
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