Question

In the circle below, Ab and CD are chords intersecting at E if AE=5, BE,12, and CE=6, what is the length of DE

Answer 1

Answer:

DE = 10

Step-by-step explanation:

Here, we want to find the value of DE

we use the intersecting chord principle

That will be;

CE * ED = AE * BE

we have;

6 * DE = 5 * 12

DE = (5 * 12)/6

DE = 5 * 2

DE = 10