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Butoxors [25]
3 years ago
12

Write some uses of magnetic force​

Physics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

television,radios, microwave ovens, telephone system and computer

AVprozaik [17]3 years ago
4 0
(i). Compass.
(ii). MRI Scanners.
(iii). Electric Motor.
(iv). Speakers.
(v). Refrigerators.
(vi). Computer.
(vii). Microwave.
(viii). Cars.
You might be interested in
Physics please help me.
Dafna1 [17]

Answer:

F = 780 [N]

Explanation:

To solve this problem we must use newton's second law which tells us that the sum of forces on a body must be equal to the product of mass by acceleration

ΣF =m*a

where:

F = force [N] (units of Newtons)

m = mass = 2600 [kg]

a = acceleration = 0.3 [m/s²]

F = 2600*0.3

F = 780 [N]

5 0
3 years ago
What’s the answer pls heellllppppppp.
Firlakuza [10]

Answer:

D.

C..........,......

5 0
3 years ago
A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min. How far does the car travel whil
Vesna [10]

Explanation:

<u>Using Equations of Motion</u> :

(1) v = u + at

24 = 6.5 + a * 210

<u>a (Acceleration) = 0.083 m/s^2 </u>

<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS

S = 576 - 42.25 / 0.166

<u>S (Distance travelled) = 3215.3 m </u>

(Option A seems a typo since the answer is 3215.3 m)

4 0
3 years ago
Calculate the work done by a 47 n force pushing a 0.025 kg pencil 0.25 m against a force of 23.
inna [77]
Fnet=fa-fr
=47-23
=24n
W=F∆Xcos°
=24n×0.025cos0
=0.6J
8 0
3 years ago
An astronaut and his space suit have a combined mass of 157 kg. The
alexgriva [62]

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]

6 0
3 years ago
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