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Art [367]
4 years ago
11

I'm giving out a lot of points for whoever helps me and answers correctly! 3 questions to answer! Please answer them ALL!!! :D

Physics
2 answers:
lions [1.4K]4 years ago
5 0

1-a 2-b 3-b    

srry had to write more, i go to this school














                                                                                                                 

Lemur [1.5K]4 years ago
3 0

1. A) A ball sits motionless on the ground

Newton's First Law of inertia states that:

"When the forces acting on an object are balanced, the object stays at rest (if it was at rest) or continues its motion with constant velocity (if it was in motion)"

Among the options given, we see that the option

A) A ball sits motionless on the ground

is an example of this law: in fact, the ball sits at rest on the ground, the forces acting on it are balanced, so the ball stays at rest.

2. B) The earth pulls more on the shuttle

The gravitational attraction exerted by a planet on the shuttle is given by

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the shuttle

r is the distance between the shuttle and the planet

In this problem, we are comparing the gravitational pulls exerted by the Earth and the Moon on the shuttle. The distance, r, is the same (because the shuttle is half-way), the mass of the shuttle m is the same, and G is the same. However, the mass of the Earth is greater than the mass of the Moon, so in the formula M is greater for the Earth: therefore, the Earth pulls more on the shuttle.

3. B) The velocity of the car reduced from 50 km/h to 35 km/h over one minute

The acceleration of the car is defined as the ratio between the change in velocity and the time taken:

a=\frac{v_f-v_i}{\Delta t}

where vf is the final velocity, vi is the initial velocity, and \Delta t is the time taken.

In order to have a negative acceleration, the numerator must be negative: this means that the initial velocity, vi, must be greater than the final velocity, vf, and this situation occurs in option B), since the initial velocity is 50 km/h while the final velocity is 35 km/h.

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A train car of mass 3,825 kg sits at rest on the track. A second car of mass 5,169 kg moving at 6 m/s slams into it and they sti
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The final combined speed of the two trains is 3.4 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.

Therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 3,825 kg is the mass of the first train

u_1 = 0 m/s is the initial velocity of the first train, which is at rest

m_2 = 5,169 kg is the mass of the second train

u_2 = 6 m/s is the initial velocity of the second train  

v is the final combined velocity of the two trains  after the collision

We can now solve the equation for v, to find the final combined velocity of the two trains:  

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{0+(5169)(6)}{3825+5169}=3.4 m/s

So, the final combined speed is 3.4 m/s.

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You throw a softball (of mass 300 g) straight up into the air. It reaches a maximum altitude of 10.1 m and then returns to you.
Marysya12 [62]

Answer

given,

mass of the ball = 300 g

                           = 0.3 Kg

maximum altitude of the ball = 10.1 m

Potential energy of the softball:

PE = m g h

PE = 0.3 x 9.8 x 10.1

PE = 29.69 J

Maximum kinetic energy at which the ball is released from hand to reach height of 10.1 m is 29.69 J.

Kinetic energy at which ball returns to your hand is equal to 29.69 J.

speed of the ball

KE=\dfrac{1}{2}mv^2

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Help me find the word of this definition
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Answer:

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