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topjm [15]
4 years ago
7

At what speed relative to the ship does she recoil toward the spaceship?

Physics
1 answer:
Andre45 [30]4 years ago
7 0
She recoil at a high speed than a low
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Two narrow slits 0.02 mm apart are illuminated by light from a CuAr laser (λ = 633 nm) onto a screen. a) If the first fringe is
Masja [62]

Answer:

a) 0.063m

b) 2.72°

c) 3151 fringes

d) 1.87*10^-6m

Explanation:

a) To find the screen distance you use the following formula:

y=\frac{m\lambda D}{d}\\\\D=\frac{dy}{m\lambda}

D: screen distance

d: distance between slits

m: order of the fringes

λ: wavelength

By replacing the values of the parameters you obtain:

D=\frac{(0.02*10^{-3}m)(0.2*10^{-2}m)}{(1)(633*10^{-9}m)}=0.063m

b) The condition for dark fringes is given by:

\lambda(m+\frac{1}{2})=dsin\theta

for the first dark fringe the angle is:

\theta=sin^{-1}(\frac{\lambda(m+\frac{1}{2})}{d})\\\\\theta=sin^{-1}(\frac{(633*10^{-9}m)(1+\frac{1}{2})}{0.02*10^{-3}m})=2.72\°

c) the visible number of fringes is given by:

N=1+2\frac{D}{d}=1+\frac{0.063m}{0.02*10^{-3}}=3151 \ fringes

d) the wavelength of a laser in which its first order fringe coincides with the third one of the CuAr laser is:

y=\frac{(3)(633*10^{-9}m)(0.063m)}{0.02*10^{-3}m}=5.98*10^{-3}m\approx0.59cm\\\\\lambda'=\frac{dy}{mD}=\frac{(0.02*10^{-3}m)(0.59*10^{-2}m)}{(1)(0.063m)}=1.87*10^{-6}m

4 0
3 years ago
Which of these physical quantities varies as an object changes its velocity? A. pressure B. mass C. weight D. momentum
kompoz [17]
I believe the answer is B
5 0
3 years ago
Read 2 more answers
Intelligence tests that are given to participants in groups
White raven [17]

<span><span>a. are typically paper-and-pencil measures.</span>


Similar with psychological tests, mostly structured personality tests.

Psychological tests comes two ways: </span>
<span>The structure psychological tests or, objectives tests and </span>unstructured psychological tests or, also called projective tests<span>. By what you are referring the responder strongly asserts a projective tests which in definition comes with an unambiguous stimuli or no paper test just drawings and images. If what the responder’s suggesting is correct you are referring to the </span>Rorschach projective tests, these tests are a figure symmetrically placed in an inkblot that lets you visualize or create a mental picture out of it, and makes you describe what you in see much detail as you can.<span>
</span>


4 0
3 years ago
A testable explanation that's supported or refuted is called a/an
elena-14-01-66 [18.8K]
The answer should be D. hypothesis
4 0
4 years ago
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(1 point) A frictionless spring with a 6-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 50 new
guapka [62]

Answer:

x(t) = 0.077cos(6.455t)

Explanation:

If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:

k = 50 / 0.2 = 250 N/m

The equation of simple harmonic motion is as the following:

x(t) = Acos(\omega t - \phi)

where \omega = \sqrt{k/m} = \sqrt{250 / 6} = 6.455

We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:

v_{max} = A\omega

A = v_{max}/\omega = 0.5 / 6.455 = 0.077 m

\phi = 0 is the initial phase

Therefore, the position of the mass after t seconds is

x(t) = 0.077cos(6.455t)

6 0
3 years ago
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