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topjm [15]
4 years ago
7

At what speed relative to the ship does she recoil toward the spaceship?

Physics
1 answer:
Andre45 [30]4 years ago
7 0
She recoil at a high speed than a low
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Is a glacier nothing more than a huge mineral flowing downhill?
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Yes. A glacier is nothing more than a huge mineral flowing downhill.
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4 years ago
An ant climbs to the very end of the second hand on a wall-mounted clock at exactly 9:15:00. The second hand is 13.5 cm long. Wh
Mekhanik [1.2K]

Answer:

Explanation:

a) The second arm measures the minutes. The difference between 9:17:30 and 9:15:00 is 2 minutes 30 seconds. This means the second arm would have revolved 2.5 times.

The circumference = 2πr= 2π(13.5 cm) = 84.823 cm

Distance = 2.5 × 84.823 cm = 212 cm = 2.12 m

b) Displacement of an object is the shortest distance between the initial and final point. Since the second arm revolves 2 and half times, we use only the half times (a semicircle)

Displacement for semicircle = 2r = 2(13.5) = 27 cm

c) Average speed = distance / time

time = 2 minutes 30 seconds = 150 seconds

Average speed = 212 cm / 150 s = 1.41 cm/s

d) Average velocity = displacement / time = 27 cm / 150 s = 0.18 cm/s

e) number of revolutions = 100 m / circumference = 100 m / 0.848 m = 117.92

but 1 revolution = 1 minute

117.92 revolution = 117 minutes 55 seconds = 1 hour 57 minutes 55 seconds

Hence the time would be: 11:12:55

3 0
3 years ago
a ball thrown vertically downwatd stikes a horizontal surface with a speed of 15 meters per seconds if then bounces and reaches
Anna71 [15]

but why was it thrown is the real question

3 0
3 years ago
Pls help i have 5 minutes
anyanavicka [17]

Number order:

5, 4, 3, 2, 1

7 0
4 years ago
Read 2 more answers
A 42.0-kg parachutist is moving straight downward with a speed of 3.85 m/s. (a) If the parachutist comes to rest with constant a
RideAnS [48]

Answer:

-414.96 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2

F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N

The force the ground exerts on the parachutist is -414.96 N

If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase

5 0
3 years ago
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