I need help with this please

Nine children and six adults bought tickets to the circus.

tamaranim1 [39]

Answer:

below

Step-by-step explanation:

9c + 6a = total cost

7 0

2 years ago

Need help with this geometry question, solving for x and please explain the formula for this

Alborosie

Alright, so what we can take as a given is that arcDE/2= ∠CDE=2x+20 since the arc corresponding to the angle is 2*the angle. To solve for arcDE, we multiply both sides by 2 to get 2(2x+20)=4x+40=arcDE. Since the arcs in a circle add up to 360 degrees and we only have -20+30x and arcDE, we have -20+40+4x+30x=360 using the associative property. Simplifying, we get 20+34x=340. Subtracting 20 from both sides, we get 340=34x. Next, we can divide both sides by 34 to get 10=x.

3 0

2 years ago

Find the polar coordinates corresponding to a point located at (- 4 .02, 11.64) in Cartesian coordinates

horsena [70]

The answer would be by drawing a graph to help u get the correct answer and once you do that messeage me back the correct answer.

5 0

2 years ago

A major retail clothing store is interested in estimating the difference in mean monthly purchases by customers who use the stor

faust18 [17]

Answer:

Critical value is t = 1.9901

Step-by-step explanation:

We are given the results of the sampling :

In-House Credit Card National Credit Card Sample Size : 32 50

Mean Monthly Purchases : $45.67 $39.87

Standard Deviation : $10.90 $12.47

Also, the managers wished to test whether there is a statistical difference in the mean monthly purchases by customers using the two types of credit cards, using a significance level α of 0.05.

Firstly, we will specify our null and alternate hypothesis;

Let $\mu_1$ = Mean Monthly Purchases of In-House Credit Card

$\mu_2$ = Mean Monthly purchases of National Credit Card

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in the mean monthly purchases by customers using the two types of credit cards}

Alternate Hypothesis, $H_0$ : $\mu_1-\mu_2\neq$ 0 {means that there is statistical difference in the mean monthly purchases by customers using the two types of credit cards}

The test statistics that will be used here is Two-sample t-test statistics;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n___1+n_2-_2$

where, $\bar X_1$ = Sample mean Purchases of In-House Credit Card = $45.67

$\bar X_2$ = Sample mean Purchases of National Credit Card = $39.87

$s_p$ = pooled variance

$n_1$ = In-house credit card sample = 32

$n_2$ = National credit card sample = 50

So, degree of freedom of t-value here is (32 + 50 - 2) = 80

Now, at 0.05 significance level, t table gives critical value of t = 1.9901 at 80 degree of freedom.

Therefore, the critical value assuming the population standard deviations are not known but that the populations are normally distributed with equal variances is t = 1.9901.

3 0

3 years ago

Rewrite the expression by using the distributive property and collecting like terms 1/5(5x-15)-2x

inessss [21]

Answer:

-x-3

Step-by-step explanation:

First, you need to distribute the 1/5 to both the term 5x and the term -15, which requires multiplication. This gives you 1x-3. The -2x can then be added on to this equation, which gives you 1x-3-2x. Combining the like terms of 1x and -2x gives you -x. The entire expression is then -x-3.

3 0

2 years ago