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3 years ago

Six Pepperidge Farm bagels were weighed, yielding the following data (grams):

Mathematics

1 answer:

ratelena [41]3 years ago

6 0

Answer:

A) Average weight = 112.97

standard deviation = 3.913

B) 119.4069

Step-by-step explanation:

A) Estimate the true average weight and standard deviation of the weight

attached below is a detailed solution

Average weight = 112.97

standard deviation = 3.913

B) Assuming a normal distribution Estimate the weight below

attached below is a detailed solution

= 119.4069

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What is the solution to the equation?

UkoKoshka [18]

$\frac{1}{3}x+\frac{1}{3}(2x-15)=3\frac{1}{2}\\\\
\frac{1}{3}x+\frac{1}{3}(2x-15)=\frac{7}{2}\ \ \ |Multiply\ by\ 6\\\\
2x+2(2x-15)=21\\\\
2x+4x-30=21\\\\
6x-30=21\ \ |Add\ 30\\\\
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\boxed{x=\frac{51}{6}=8\frac{1}{2}}$

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3 years ago

A four year old is going to spin around with his arms stretched out 100 times. From past experience, his father knows it takes a

Sati [7]

Answer:

$P(X \geq0.55) \leq 0.22$

Step-by-step explanation:

Using central Limit Theorem (CLT), The sum of 100 random variables;

$Y=X_1+X_2+...+X_{100}$ is approximately normally distributed with

Y ~ N (100 × $\frac{1}{3^2}$ ) = N ( 50, $\frac{100}{9}$ )

The approximate probability that it will take this child over 55 seconds to complete spinning can be determined as follows;

N ( 50, $\frac{100}{9}$ )

$P(Y>55) =P(Z>\frac{55-50}{10/3})$

$P(Y>55) =P(Z>1.5)$

$P(Y>55) =\phi (-1.5)$

$P(Y>55) =0.0668$

Using Chebyshev's inequality:

$P(|X-\mu\geq K)\leq \frac{\sigma^2}{K^2}$

Let assume that X has a symmetric distribution:

Then:

$2P(X-\mu\geq K)\leq) \frac{\sigma^2}{K^2}$

$2P(X \geq \mu+K)\leq) \frac{\sigma^2}{K^2}$

$2P(X\geq0.5+0.05)\leq \frac{\frac{1}{\frac{3^2}{100} } }{0.05^2}$ where: ( $\sigma^2 = \frac{1}{3^2/100}$ )

$P(X \geq0.55) \leq 0.22$

6 0

3 years ago

Which expression has a value of 20?

Mice21 [21]

Answer:

the fist one is equal to 20

8 0

3 years ago

The sum of three certain consecutive numbers is 240. Find the three numbers. [Hint: Let x stand for the smallest number. Since t

aleksley [76]

Write an equation based on the problem in the terms of x and solve the equation
first number + second number + third number = 240
x + x + 1 + x + 2 = 240
3x + 3 = 240
3x = 240 - 3
3x = 237
x = 237/3
x = 79
The smallest number, x, is equal to 79

Find the next two numbers
the second number = x + 1
the second number = 79 + 1
the second number = 80

the third number = x + 2
the third number = 79 + 2
the third number = 81

ANSWER: The three numbers are 79, 80, 81

7 0

3 years ago

There are 52 cards in a deck, and 13 of them are hearts. Four cards are dealt, one at a time, off the top of a well-shuffled dec

irga5000 [103]

Answer:

10.97%

Step-by-step explanation:

There are 52 cards.

13 of them, are hearts.

Then

52 - 13 = 39 cards are not hearts.

4 cards are drawn, we want to find the percent chance that the fourth card is a heart card, but no before.

So the first card can't be a heart card.

because the deck is well-shuffled, all the cards have the same probability of being drawn.

Then the probability of not getting a heart card, is equal to the quotient between the number of non-heart cards (39) and the total number of cards (52), then the probability is:

p₁ = 39/52

The second card also can't be a heart card, the probability is calculated in the same way than above, but now there are 38 non-heart cards and a total of 51 cards (because one card was already drawn) then the probability here is:

p₂ = 38/51

For the third card the reasoning is similar to the two above cases, here the probability is:

p₃ = 37/50

The fourth card should be a hearts card, the probability is computed in the same way than above, as the quotient between the number of heart cards in the deck (13) and the total number of cards in the deck (now there are 49 cards)

then the probability is:

p₄ = 13/49

The joint probability (the probability of these 4 events happening together) is equal to the product between the individual probabilities:

P = p₁*p₂*p₃*p₄

P = (39/52)*(38/51)*(37/50)*(13/49) = 0.1097

The percent chance is the above number times 100%

Percent = 0.1097*100% = 10.97%

3 0

3 years ago