<span>16 walls in 40 hours
3 walls in h hours
16/40 = 3/h
16h = 40(3)
16h = 120
h=120/16
h=7.5
answer: </span><span>3 walls in 7.5 hours</span>
We know that
<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
Answer:
78
Step-by-step explanation:
180-90-12=78
Answer:
69
Step-by-step explanation:
U = vw + z
vw + z = u |subtract z from both sides
vw = u - z |divide both sides by w
v = (u - z)/w