Given what we know about the correlation between the liver temperature of a corpse and the estimated TOD, we can conclude that the estimated time of death is approximately 10:30 pm of the night before.
<h3>How do we estimate the TOD?</h3>
- This can be achieved using a mathematical formula.
- The formula in question involves taking the normal body temperature of a living human and subtracting the liver temperature of the body.
- The remaining is the difference in temperature.
- Given that a body will lose roughly 1.5 degrees worth of heat per hour, we divide the remaining number by this to get the amount of hours since the death.
- This leads us to the conclusion that this individual perished roughly 15.5 hours earlier.
Therefore, given the way in which we use the correlation between liver temperature and time to analyze and approximate a time of death, we can confirm that this individual will have perished at roughly 10:30 pm of the night before.
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Explanation:
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Answer:
d
Explanation:
as a result of accumulation of waste products in the body , these substances are removed from the body via the skin hence they undergo cellular respiration
There are choices for this question namely:
<span>a. K+ leaks into cells.
b. Voltage-gated Na+ channels become inactivated.
c. Voltage-gated K+ channels become inactivated.
d. Na+ reaches equilibrium across the neural membrane and stops leaking in.
e. Voltage-gated Na+ channels close.
The correct answer is "voltage-gated Na+ channels become inactivated". In the events concerning an action potential, the first event is a stimulus that depolarize the resting membrane potential up to the threshold. When the threshold is reached there will be opening of voltage gated Na+ channels wherein sodium can enter the cell and make the membrane more positive therefore called depolarization. After depolarization, voltage gated Na+ channels become inactivated and K+ leaks out of the cell making the cell less negative hence repolarization. After which, more and more K+ ions leaks out making the membrane more negative than the resting membrane potential hence hyperpolarization. When K+ channels are inactivated, the cell membrane will eventually go back to its resting membrane potential.</span>
