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Licemer1 [7]
3 years ago
5

Can someone plz help me!!!

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0

Answer:

1 or I

Step-by-step explanation:

vfiekz [6]3 years ago
4 0
Answer: Quadrant I


I’ve answered one of your questions before. Try to remember or at least take a photo of the info and cheats I gave you.
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Can anyone help solve algebra 2?<br> (4x)^(4/3)
Fantom [35]

See picture for solution steps and answer.

5 0
3 years ago
Vin charges $25 rent each day for a booth at his flea market if4 people rent a booth Saturday,and 4 people rent a booth Sunday h
Bezzdna [24]

Answer:

$200

Step-by-step explanation:

Vin charges $25 each day for a booth at the flea market

4 people rented the booth on Saturday

= 25 × 4

= $100

4 people rented the booth on Sunday

= 25 × 4

= $100

Therefore the amount of rent collected by Vin can be calculated as follows

= $100 + $100

= $200

5 0
3 years ago
Y=2x+0.5 I have to solve this using a weird table and then I have to graph it. How?
g100num [7]
You have to choose any input ,plug it in the equation ,solve it and look what is the output.Do that for the rest of the points . when you finish graph your points.
5 0
4 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
The diagram is a floor plan for a new building. Find the perimeter.
lara31 [8.8K]

Answer:

154

Step-by-step explanation:

perimeter is the area all round, basically you sum all the measurements

4 0
2 years ago
Read 2 more answers
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