Starting off, we can multiply the third equation by 2 and add it to the third to get rid of both the x and y variables. Next, we get z=1. Plugging that into 3y-5z=-23, we get 3y-5=-23. Adding 5 to both sides, we get 3y=-18. After that, we can divide both sides by 3 to get y=-6. Plugging that into -2x-y-z=-3, we get -2x+6-1=-3=-2x+5. Subtracting 5x from both sides, we get -2x=-8. After that, we can divide both sides by -2 to get x=4.
Answer:
(4, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 2x - 7
y = -x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x - 7 = -x + 5
- [Addition Property of Equality] Isolate <em>x</em> terms: 3x - 7 = 5
- [Addition Property of Equality] Isolate <em>x</em> term: 3x = 12
- [Division Property of Equality] Isolate <em>x</em>: x = 4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -x + 5
- Substitute in <em>x</em>: y = -4 + 5
- Add: y = 1
It will be b after you do the math
Answer:
The answer is sometimes.
If the two lines have the same slope, then there will be 0 solutions, and if the two lines are the same, then there will be infinite solutions.
Hope this helps!
Answer:
let the past stay in the past
Step-by-step explanation:
