X+3y=3
First add subtract the x
3y=-x+3
Then divide 3
Y=-1/3x+1
Answer:
A 2
Step-by-step explanation:
When we divide x by 9 there is some whole number we will call y plus a remainder of 4
x/9 = y remainder 4
Writing this in fraction form
x/9 = y + 4/9
Multiplying each side by 9
9*x/9 = 9* y + 4/9 *9
x = 9y +4
Multiply each side by 2
2x = 2*(9y+4)
2x = 18y +8
Add 3 to each side
2x+3 = 18y +8+3
2x+3 = 18y +11
Divide each side by 9
(2x+3)/9 = 18y/9 +11/9
= 2y + 9/9 +2/9
=(2y+1 + 2/9)
We know y is a whole number and 1 is a whole number so we can ignore 2y +1 when looking for a remainder)
2/9 is a fraction
Taking this back from fraction form to remainder from
(2y+1) remainder 2
Yeah Thanks I love to see that and the answer A
Answer:
No solution
Step-by-step explanation:

Lets consider the equation 2.
Here we multiply the LHS and RHS with (-1).

Hence,

When we add the equations we get,

As 0 doesn't equal to -1, answer is d) No solution