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Komok [63]
3 years ago
14

I got the answer but I don't understand what the -1 does

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0
The -1 affects the coefficient of the entire term.

Without the -1,
the term has a positive coefficient.
(3a)² = 9a²

However, with the -1,
the term has a negative coefficient.
-(3a)² = -9a²
kramer3 years ago
6 0
What he said sounds correct
You might be interested in
Does 3 work as a solution to the following inequality? 2n > 6
Ksju [112]

Answer:

No.

Step-by-step explanation:

If n=3 the only thing you get is 6, which is not more than 6.

5 0
3 years ago
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
The price of a video game was reduced from $70.00 to $40.00. By what percentage of the price was was the videogame reduced? Just
olya-2409 [2.1K]

Answer:

42.86%.

Step-by-step explanation:

Reduction in price = $70.00 - $40.00 = $30.00

Reduction in percentage = ($30.00 ÷ $70.00) x 100 = 42.86%

The price of the videogame was reduced by 42.86%.

8 0
3 years ago
Read 2 more answers
Please answer this correctly which is the correct options
MakcuM [25]

The first two are equivalent to 15 = k + 13

8 = k + 13 - 7 → ( add 7 to both sides )

8 + 7 = k + 13 ⇒ 15 = k + 13 ' is equivalent '

12 = k + 13 - 3 → ( add 3 to both sides )

12 + 3 = k + 13 ' is equivalent '


4 0
3 years ago
GEOMETRY PLEASE HELPPP!! WILL MARK BRAINLIEST
MaRussiya [10]
I think the answer is the 3rd rectangle but I'm not too sure I'm sorry
4 0
3 years ago
Read 2 more answers
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