Answer:
1+1=2
Step-by-step explanation:
are you freaking serious bro?
Answer:
all the numbers in set a would all round to 0
<span>Answer:</span><span>
<span>B) The maximum height is 11.3 ft and it reaches this height at 0.72
seconds.
</span>Explanation:
Part (a) : getting the
time taken to reach maximum height:
The given equation is:
h = -16t² + V0*t + h0
We are given that:
Initial velocity (V0) =23 ft/sec
Initial height (h0) = 3 ft
The equation now becomes:
h = -16t² + 23t + 3
For maximum height:
dh / dt = zero
This means that:
-16(2) t + 23 = 0
-32t + 23 = 0
32t = 23
t = 0.71875 sec which is approximately 0.72 seconds
Part (b): getting the
maximum height:
The equation given to get the height is:
h = -16t² + V0*t + h0
We are given that:
Initial velocity (V0) =23 ft/sec
Initial height (h0) = 3 ft
We have calculated that:
time taken to reach maximum height = 0.72 sec
Substitute with the givens in the equation to get the maximum
height as follows:
h = -16t² + V0*t + h0
h = -16(0.72)² + 23(0.72) + 3
h = 11.2656 ft which is approximately 11.3 ft
Hope this helps :)</span>
Hi there
a)244,000−244,000×0.20=195,200
b) pmt=pv÷[(1-(1+r/k)^(-kn))÷(r/k)]
Pmt=195,200÷((1−(1+0.055÷12)^(−12×30))÷(0.055÷12))=1,108.32
Hope it helps
Answer:
a
Step-by-step explanation: