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Mnenie [13.5K]
3 years ago
12

What is the slope of the line? NEED ASAP WILL MAKE BRAINLIEST

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

2

Step-by-step explanation:

To find the slope, we  use the equation

m = (y2-y1)/(x2-x1)

Since the have the points (2,-4) and (4,0)

m = (0--4)/ (4-2)

   = (0+4)/(4-2)

   = 4/2

   =2

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The area of a square is 144cm2.what is the measurement of each side​
Dmitry [639]

The area of a square is 144 cm^2. The measurement of each side​ is 12 cm

<u>Solution:</u>

Given, The area of a square is 144 cm^2

We have to find that what is the measurement of each side.

Now, we know that, area of a square = product of side value with another side value.

Let the side value of given square be "s"

Then, <em>Area of square is given as:</em>

\begin{array}{l}{\text {area of square}=s \times s} \\\\ {\text {Area of square}=s^{2}} \\\\ {144=s^{2}} \\\\ {s=\sqrt{144}} \\\\ {s=\sqrt{12^{2}}}\end{array}

On cancelling square root and square on right side,we get

s = 12

Hence, the side value of the square is 12 cm.

8 0
3 years ago
What is the slope of the line that passes through the pair of points (2,12 and (6,11?
Sedaia [141]

slope = difference in y / difference in x

slope = 12 -11 / 2 -6

slope = 1 / -4

slope = -1 / 4 or

-.25

7 0
3 years ago
The midpoint of RT is S(0.5, –6.25). One endpoint is T(–5.5, 2.75). What are the coordinates of R?
IrinaK [193]
<span>(6.5, –15.25) Is the answer.</span>
5 0
3 years ago
Read 2 more answers
BRAINY
likoan [24]

Answer:

correct answer is four sixths

Step-by-step explanation:

you can simplify 2/6 to 1/3 and then it would just be 1/3 plus 1/3. This is 2/3 or 4/6! Hope this helps :)

5 0
3 years ago
Will someone please answer these questions fast and I will give the brainliest? I really need help and it would be appreciated.
Anika [276]

Hello there,

(1) $7934.37

interest would be $2934.37

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interest would be $1593.74

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interest would be $796.87

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interest would be $139.66

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interest would be $3660.96


Hope I Helped!

-Char



7 0
3 years ago
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