From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
Answer:
hard question you got there
Step-by-step explanation:
Answer:
Approximately 24–36 pounds
Step-by-step explanation:
Given:
Weight of standard American Eskimo dog has mean= 30 pounds
A standard deviation= 2 pounds
For 99.7% of the dogs according to normal distribution would lie between 3 standard deviations on either side of the mean.
i.e. lower bound= Mean- 3 (standard deviation)
= 30-3(2)
=30-6
=24
Upper bound = Mean +3 (standard deviation)
= 30+3(2)
=30+6
=36
Hence the range of weights : 24-36 pounds
correct answer Approximately 24–36 pounds!
Answer:
B
Step-by-step explanation:
each time she sells 2 cards she gets $9 right?
so counting by 2's is the best route to go on and the only answer that displays that is answer B
Following the principle of supplements angles, the angle next to the 101 is 79°. 79+38+c(call the third angle c) = 180
c = 180-117 =63° x is supplemental to c so 180 = x +c
180=x + 63
x =117
