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Simora [160]
3 years ago
7

An arc that measures 180 degrees is called a

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
An arc that measures 180 degrees is called a semicircle.

If it measures less than 180 it’s a minor arc.

If it measures greater than that it’s called a major arc
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Can someone answer questions 2 - 7 for me please?
MrRissso [65]
<span>Question No.2
</span>
speed= distance/ time  

1200km/0.006s= 200 000 km/s 

<span>Question 4
</span>
wavelength = wavespeed / frequency 

wavespeed = 16/8 = 2 

Question 5

(400/60s) = 6.6667 waves/ sec (Hz). 
<span>Velocity = 0.008m/sec. </span>
<span>Wavelength = (v/f) = 0.008/6.6667 = 0.0012 metre (1.2mm).
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8 0
3 years ago
18. A store sells two different kinds of rulers, plastic and wood. The receipts show that they have sold 35 total rulers today.
kvv77 [185]

Answer:

12 wooden rulers

23 plastic rulers

Step-by-step explanation:

Total rulers sold - 35

Total profit - $82

1 wooden ruler - $3

1 plastic ruler - $2

$3 x 12 = $36

$2 x 23 = $46

$46 + $36 = $82

12 + 23 = 35 rulers

3 0
3 years ago
Proof that x^y + y^x &gt; 1 for all x,y &gt; 0 ...?
bekas [8.4K]
To prove this inequality we need to consider three cases. We need to see that the equation is symmetric and that switching the variables x and y does not change the equation.

Case 1: x >= 1, y >= 1

It is obvious that

 x^y >= 1, y^x >= 1
 x^y + y^x >= 2 > 1
 x^y + y^x > 1

Case 2: x >= 1, 0 < y < 1

 Considering the following sub-cases:

  - x = 1, x^y = 1
  - x > 1,

    Let x = 1 + n, where n > 0

    x^y = (1 + n)^y = f_n(y)

    By Taylor Expansion of f_e(y) around y = 0,

    x^y = f_n(0) + f_n'(0)/1!*y + f_n''(0)/2!*y^2 + ...
        = 1 + ln(1 + n)/1!*y + ln(1 + n)^2/2!*y^2 + ...

    Since ln(1 + n) > 0,

    x^y > 1

  Thus, we can say that x^y >= 1, and since y^x > 0.

  x^y + y^x > 1

  By symmetry, 0 < x < 1, y >= 1, also yields the same.

Case 3: 0 < x, y < 1

  We can prove this case by fixing one variable at a time and by invoking symmetry to prove the relation.

  Fixing the variable y, we can set the expression as a function,

  f(x) = x^y + y^x
  f'(x) = y*x^(y-1) + y^x*ln y 
  For all x > 0 and y > 0, it is obvious that
  f'(x) > 0.

  Hence, the function f(x) is increasing and hence the function f(x) would be at its minimum when x -> 0+ (this means close to zero but always greater than zero). 

  lim x->0+ f(x) = 0^y + y^0 = 0 + 1 = 1

  Thus, this tells us that 

  f(x) > 1.

  Fixing variable y, by symmetry also yields the same result: f(x) > 1.

  Hence, when x and y are varying, f(x) > 1 must also hold true.
    Thus, x^y + y^x > 1.

We have exhausted all the possible cases and shown that the relation holds true for all cases. Therefore, 

<span>  x^y + y^x > 1


----------------------------------------------------

I have to give credit to my colleague, Mikhael Glen Lataza for the wonderful solution.


I hope it has come to your help.

</span>
6 0
4 years ago
Really important 70 points)Which statement about the product is true? 25.9578. The product is irrational. The product is neither
Rzqust [24]
If you can make a fraction with it it is rational hope that helps
3 0
3 years ago
Read 2 more answers
Solve for c <br><br>solve for r<br>​
expeople1 [14]

Answer:

Step-by-step explanation:

9(c+7)=27

9c+63=27  subtract 63 from both sides

9c=  -36  divide by 9

c= -4

3(2r-8)+4r=76 foil

6r-24+4r=76 combine like terms

10r-24=76 add 24 to both sides

10r+100  divide by 10

r= 10

7 0
3 years ago
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