What is the area of a rectangle that is 12 cm long and 2 cm wide?
2 answers:
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Answer:
C
Step-by-step explanation:
From the given coordinates
A(6, 0), B(0, 0) then AB = 6 - 0 = 6
B(0, 0), C(0, 8) then BC = 8 - 0 = 8
To calculate AC use Pythagoras' theorem on the right triangle formed
AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100
Take the square root of both sides, hence
AC = = 10
Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C
Answer:
D. y²/5² - x²/8² = 1
Step-by-step explanation:
A and B are both incorrectly oriented, and D is the only hyperbola that contains the points (0,5) and (0,-5).
Verification (0,5) and (0,-5) are in the hyperbola:
First replace x and y with corresponding x and y values (We will start with x=0 and y=5)
Then simplify.
If the result is an equation (where both sides are equal to each other) then the original x and y values inputted are valid. The same is true with x and y inputs x=0 and y=-5, or any other point along the hyperbola.