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Anna35 [415]
3 years ago
12

I will give u a crown no links will be reported edge2021

Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

(2/3, 1/5)

Step-by-step explanation:

x=2/3, y=1/5

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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = cos(θ) + sin(10
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Answer:

Step-by-step explanation:

x = cos θ + sin(10θ)

y = sin θ + cos(10θ)

Take derivative with respect to θ:

dx/dθ = -sin θ + 10 cos(10θ)

dy/dθ = cos θ - 10 sin(10θ)

Divide:

dy/dx = (dy/dθ) / (dx/dθ)

dy/dx = (cos θ - 10 sin(10θ)) / (-sin θ + 10 cos(10θ))

Evaluate the derivative at θ=0:

dy/dx = (cos 0 - 10 sin 0) / (-sin 0 + 10 cos 0)

dy/dx = 1/10

Evaluate the parametric functions at θ=0:

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