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dsp73
3 years ago
14

the price for an adult movie ticket it 1 1/3 more than a movie ticket for a child. Ines takes her daughter to the movie, buys a

box of popcorn for $5.50 and spends $26.50 write and solve an equation to find prices for each of their movie tickets
Mathematics
2 answers:
dsp733 years ago
6 0
The price of a child ticket is $9.84 and an adult ticket is $11.17
antiseptic1488 [7]3 years ago
5 0

Answer:

The cost of child ticket is $9.3.

The cost of adult ticket is $10.6.

Step-by-step explanation:

Given : The price for an adult movie ticket it 1\frac{1}{3} more than a movie ticket for a child. Ines takes her daughter to the movie, buys a box of popcorn for $5.50 and spends $26.50.

To find : Write and solve an equation to find prices for each of their movie tickets ?

Solution :

Let the price of one child ticket be 'x'.

The price for an adult movie ticket it 1\frac{1}{3}=\frac{4}{3} more than a movie ticket for a child.

i.e. The price for adult ticket is x+\frac{4}{3}

She buys a box of popcorn for $5.50.

Total cost of tickets and popcorn is x+\frac{4}{3}+x+5.50

Total she spends is $26.50.

So, x+\frac{4}{3}+x+5.50=25.50

2x=25.50-5.50-\frac{4}{3}

2x=20-\frac{4}{3}

2x=\frac{60-4}{3}

2x=\frac{56}{3}

x=\frac{56}{3\times 2}

x=\frac{28}{3}

x=9.3

The cost of child ticket is $9.3.

The cost of adult ticket is x+\frac{4}{3}=\frac{28}{3}+\frac{4}{3}=\frac{32}{3}=10.6

The cost of adult ticket is $10.6.

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8 0
3 years ago
How do you do inverse operation on a fraction ( y/3 ) = -6
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Solution:

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4 0
3 years ago
Bernard solved the equation 5x+(-4)=6x+4 using algebra tiles.Which explains why Bernard added 5 negative x-tiles to both sides i
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6 0
3 years ago
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nydimaria [60]
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5 0
3 years ago
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Please answer! Thanks
GenaCL600 [577]
1) y = 1x + 95.50
x = number of bandanas

2) y = (1 • 50) + 95.50
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