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krok68 [10]
3 years ago
6

Four balls are taken to the top of a building. ball 1 is dropped (zero initial velocity). ball 2 is thrown straight up with a ve

locity of 3 m/s. ball 3 is thrown straight out with a horizontal velocity of 3 m/s. ball 4 is thrown straight down with a velocity of 3 m/s. which ball hits the ground first?
Mathematics
1 answer:
tia_tia [17]3 years ago
4 0
The one which has the greatest initial DOWNWARD velocity which is ball 4
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Find four consecutive numbers whose sum equals 218
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53+54+55+56

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I don't remember equation but I know this is the because I can roughly estimate the numbers by dividing by four and going from there

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What is the slope of the line represented by the equation y= 4/5x-3
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m=

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For a consumer to obtain a 10% discount, he must spend an amount
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Identify the end behavior of the function f(x) = 6x^4 - 12x^3 +8x -10
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4 0
3 years ago
you want to create a 99 confidence interval with a margin of error of 25 assuming that the population standard deviation is equa
Ahat [919]

Answer:

The minimum sample size is 239.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

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That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Population standard deviation is equal to 1.5

This means that \sigma = 1.5

Margin of error of 0.25

This means that M = 0.25

What's the minimum size of the sample?

M = z\frac{\sigma}{\sqrt{n}}

0.25 = 2.575\frac{1.5}{\sqrt{n}}

0.25\sqrt{n} = 2.575*1.5

\sqrt{n} = \frac{2.575*1.5}{0.25}

(\sqrt{n})^2 = (\frac{2.575*1.5}{0.25})^2

n = 238.7

Rounding up:

The minimum sample size is 239.

4 0
3 years ago
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