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slavikrds [6]
2 years ago
8

In ΔABC, point M is the midpoint of side AB and point D is the midpoint of segment MC. Prove that the area of ΔADC= the area of

ΔBMD
Mathematics
1 answer:
Anna11 [10]2 years ago
8 0
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
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3 0
3 years ago
Help ASAP please and explain tooo
Alla [95]

Answer:

A not similar

Step-by-step explanation:

These triangles are not similar

<K would have to equal either angle E or D since angle F equals angle F

E = 50 and D = 58   and K = 49 so K does no equal E or D so they cannot be similar

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3 years ago
Sebastian has 50 marbles in a bag. 20% of the marbles are green. How many marbles are green?
Ede4ka [16]

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7 0
3 years ago
Read 2 more answers
Which decimal is equivalent to 26/9
grandymaker [24]

Answer:

The decimal 2.8 is equivalent to 26/9

Hope this helps

3 0
2 years ago
Let <img src="https://tex.z-dn.net/?f=K" id="TexFormula1" title="K" alt="K" align="absmiddle" class="latex-formula"> be a circle
yan [13]

The bisector of angle APQ passes through O and this is illustrated below.

<h3>How to illustrate the information?</h3>

From the information given, the center is O. and the circle passes through O and cuts at K.

In this case, it should be noted that the circles are equal according to the SAS test.

Here, AOB + APQ = 180° (Linear pair)

2AOB = 180

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Therefore, the bisector of angle APQ passes through O.

Learn more about bisector on:

brainly.com/question/11006922

#SPJ1

8 0
2 years ago
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