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slavikrds [6]
3 years ago
8

In ΔABC, point M is the midpoint of side AB and point D is the midpoint of segment MC. Prove that the area of ΔADC= the area of

ΔBMD
Mathematics
1 answer:
Anna11 [10]3 years ago
8 0
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
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3 years ago
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d1i1m1o1n [39]

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3 0
3 years ago
Read 2 more answers
Cameron is flying 8,000 feet above sea level. Directly below her, she sees a whale 50 feet below sea level. Which absolute value
Lesechka [4]

Answer:

D) |−8,000 − (−50)|

Step-by-step explanation:

When we are dealing with questions involving above or below sea level,

The formula for the Absolute value expression representing the distance = | Height above sea level -(Distance below sea level|

Height of Cameron above sea level = 8000ft = -8000

Distance of the whale below sea level = 50ft = -50

Hence, we have:

|−8,000 − (−50)|.

Option D is the correct option

5 0
3 years ago
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