Answer:
x ≈ 8.9
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, the the square of the tangent is equal to the product of the external part of the secant and the entire secant, that is
x² = 8(8 + 2) = 8 × 10 = 80 ( take the square root of both sides )
x = ≈ 8.9 ( to the nearest tenth )
Answer:
(A)T(–2, 4) ry-axis
Step-by-step explanation:
The graph showing triangles MNO and M"N"O" is attached below.
From the graph, the coordinates are:
When we <u>transform triangle MNO by (-2,4),</u> we obtain:
M'(3,0), N'(1,2) and O'(-1,1)
Next, we reflect M'N'O' the y-axis.
Note: When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite.
Therefore:
Therefore, the sequence of transformations could be used to map triangle MNO onto M"N"O" is T(–2, 4) ry-axis.
The correct option is A.
