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2 years ago

Can anyone help me on this problem, please? It's from a section on literal equations.

Mathematics

2 answers:

saveliy_v [14]2 years ago

7 0

145 =45+20h
100=20h
h=5

Agata [3.3K]2 years ago

4 0

If he charges $145 he worked for 5 hours at $20 an hour

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Cole wants to buy carpet to cover his whole living room, except for the tiled floor. The tiled floor is 4 5 6 ft by 2 1 3 ft. Fi

Shtirlitz [24]

Answer:

$Area = 49\frac{25}{36}$

Step-by-step explanation:

Given

Tile

$Length = 4\frac{5}{6}$

$Width = 2\frac{1}{3}$

See attachment for dimension of the floor

Required

Determine the area covered by the carpet

From the attachment, the dimension of the floor is:

$Length = 12\frac{1}{4}$

$Width = 5$

Calculate Area

$Area = Length * Width$

$Area = 12\frac{1}{4} * 5$

$Area = 61\frac{1}{4}$

The area of the tiles is:

$Area = 4\frac{5}{6} * 2\frac{1}{3}$

$Area = \frac{29}{6} * \frac{7}{3}$

$Area = \frac{203}{18}$

$Area = 11\frac{5}{18}$

So, the carpet area is:

$Area = Floor\ Area - Tile\ Area$

$Area = 61\frac{1}{4} - 11\frac{5}{18}$

To improper number

$Area = \frac{245}{4} - \frac{208}{18}$

Take LCM

$Area = \frac{2205 - 416}{36}$

$Area = \frac{1789}{36}$

$Area = 49\frac{25}{36}$

7 0

2 years ago

Scott started his banking account with $150 and is spending $7 per day on lunch what would the x axis be labeled

Mariulka [41]

X: number of days
y: money available

8 0

3 years ago

Find the product: -4/9 and -3/8

NNADVOKAT [17]

Answer:

1/6

Step-by-step explanation:

-4/9 * (-3/8) =

= 12/72

= 1/6

6 0

2 years ago

Read 2 more answers

Is 8 ,5,1 and -4 an arithmetic sequence.

kolbaska11 [484]

Answer:

The sequence is not geometric or arithmetic because there is no common difference or common ratio between each term.

Not a Geometric or Arithmetic Sequence

5 0

3 years ago

Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to

polet [3.4K]

This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 ( $14 x^{2}$ ) by changing the 14 to 0. That way we'll left with $f(x)=5x-1$ which only has one real root:
$0=5x-1$
$5x=1$
$x= \frac{1}{5}$

7 0

3 years ago

Read 2 more answers