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babymother [125]
3 years ago
13

Audra is creating a training document and would like to include an image that she sees on her screen that she has marked up for

training purposes. Which options should Audra use?
O Insert tab, Pictures
O Insert tab, Screenshot
O Insert tab, Online Images
O Insert tab, Format
Computers and Technology
2 answers:
kupik [55]3 years ago
4 0

Answer:

the first and last one

Explanation:

give me brainilest

Ksenya-84 [330]3 years ago
4 0

Answer:

A: Insert tab, pictures

Explanation:

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1. Write programming code in C++ for school-based grading system. The program should accept the Subject and the number of studen
satela [25.4K]

In this program, I am using the school-based grading system and the program should accept the subject and the number of students.

Program approach:-

  • Using the necessary header file.
  • Using the standard I/O namespace function.
  • Define the main function.
  • Declare the variable.
  • Display enter obtain marks in 5 subjects.
  • Return the value.

Program:-

//header file

#include<iostream>

//using namespace

using namespace std;

//main method

int main()

{

//declare variable

  int j;

  float mark, sum=0, a;

//display enter obtain marks in 5 subjects

  cout<<"Enter Marks obtained in 5 Subjects: ";

  for(j=0; j<5; j++)

  {

      cin>>mark;

      sum = sum+mark;

  }

  a = sum/5;

//display grade

  cout<<"\nGrade = ";

  if(a>=91 && a<=100)

//display a1

      cout<<"a1";

  else if(a>=81 && a<91)

//display a2

      cout<<"a2";

  else if(a>=71 && a<81)

      cout<<"b1";

  else if(a>=61 && a<71)

      cout<<"b2";

  else if(a>=51 && a<61)

//display c1

      cout<<"c1";

  else if(a>=41 && a<51)

//display c2

      cout<<"c2";

  else if(a>=33 && a<41)

//display d

      cout<<"d";

  else if(a>=21 && a<33)

//display e1

      cout<<"e1";

  else if(a>=0 && a<21)

//display e2

      cout<<"e2";

  else

//display invalid

      cout<<"Invalid!";

  cout<<endl;

//return the value

  return 0;

}

Learn more grading system

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3 years ago
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Answer:

i dont know

Explanation:

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Java and Python are considered rapid development programming languages?<br><br> True<br><br> False
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That is true because Java was considered a rapid development programming language
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