Question

If x = 3 (y + 2) minus 1 what is the value of w in terms of x and y?

Answer 1

Answer:

$w=\dfrac{x-3y+1}{3}$

Step-by-step explanation:

The given expression is :

x = 3 (y + w) -1

We need to find the value of w in terms of x and y.

Solving RHS of the given expression :

x = 3y+3w-1

subtracting both sides 3y.

x-3y = 3y+3w-1 -3y

x-3y = 3w-1

Add 1 both sides

x-3y+1=3w-1+1

3w=x-3y+1

$w=\dfrac{x-3y+1}{3}$

Hence, the correct option is (c) "$w=\dfrac{x-3y+1}{3}$ i.e. w = StartFraction x minus 3 y + 1 Over 3 EndFraction.