P(J / R) = P (J and R) / P(R)
<span>0.8 = P (J and R) / 0.6 </span>
<span>P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining] </span>
<span>P(J / NR) = P (J and NR) / P(NR) </span>
<span>0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4 </span>
<span>P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining] </span>
<span>Hence; </span>
<span>Propability of John practicing regardless of weather condition is </span>
<span>P(John Practicing) = 0.48 + 0.16 = 0.64</span>
Answer:
![\boxed{20 \%}](https://tex.z-dn.net/?f=%5Cboxed%7B20%20%5C%25%7D)
Step-by-step explanation:
% Increase = Increase/Original value × 100 %
Data:
Latest selling price = $20
-Original selling price = <u>- 16
</u>
Increase = $ 4
Calculations:
% increase = 4/20 × 100 % = 20 %
The percent increase is
.
X<2: 5x+7>17 you subtract seven from both sides to give you 5x>10 when you divide by 5 the sign flips to give you x<2.
8 because all elements after nitrogen have not only two energy levels, they also find it easier to just get rid of electrons than to absorb electrons to get to 8 electrons.
13, add all the number then subtract the total from them.