Please help i will give u brainliest

9.8x10^6 In standard form

liraira [26]

What do you think? Hint 6 pi

6 0

3 years ago

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Need help on geometry please right answer only I’m giving out 40 points

Juliette [100K]

Answer: first option 392.699 square feet.

Explanation:

1) The shape of the sidewalk is an ring with exterior radius equal to the radious of the fountain + 5 feet and inner radius equal to the radius of the fountain.

2) The area of such ring is equal to the area of the outer circle less the area of the inner circle (the fountain)

Area of a circle = π × r²

Area of the outer circle: π (10ft + 5 ft)² = π (15 ft)² = 225 π ft²

Area of the inner circle = π (10ft)² = 100 π ft²

Area of the ring (sidewald) = 225π ft² - 100π ft² = 125π ft² = 392.699 ft²

6 0

3 years ago

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

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Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para

kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) $P(X \leq 8) = 0.932$ (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) $P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032$ (cumulative)

(d) $P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316$ (cumulative)

(e) $P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251$

5 0

3 years ago

A 12-meter ladder leans against a building forming a 30° angle with the building.

KatRina [158]

Answer:

will show you two (2) ways to solve this problem.

A diagram is needed to see what is going on....

Without loss of generality (WLOG)

The wall is on the right. The ladder leans against the wall

with a POSITIVE slope, from SW to NE (quadrant 3 to quadrant 1).

The measure from the bottom of the ladder to the wall is 6.

Option 1:

The ladder, ground and wall form a right triangle.

The hypotenuse (ladder) is 14 feet.

The bottom of the ladder is 6 feet from the wall,

so the base of this right triangle is 6 feet.

The top of the ladder to the ground represents

the missing leg of the right triangle.

The pythagorean theorem applies, which says

6^2 + h^2 = 14^2 where h is the height

of the top of the ladder to the ground

36 + h^2 = 196

h^2 = 196 - 36

h^2 = 160

h = sqrt(160)

= sqrt(16 * 10)

= sqrt(16)* sqrt(10)

= 4*sqrt(10) <--- exact answer

= 4 * 3.16227766016838....

= 12.64911....

12.65 <--- rounded to 2 digits as directed

----------------------------------------------

Option #2: using trig

With respect to the angle formed by the bottom of the

ladder with the ground

cos T = 6/14 = 3/7

T = inverse-cosine(3/7) = 64.623006647 degrees

sin(64.623006647) = h/14

h = 14*sin(64.62300647) = 12.6491106 <--- same answer

hope this helps

Step-by-step explanation:

5 0

3 years ago