Answer:
Step-by-step explanation:
slope intercept form => Y = mx + b
find m... the slope by using any two points on the line
p1 = (0,5) by inspection
p2=(4,6) by inspection
find m = y2-y1 / x2-x1
m = 6 - 5 / 4 - 0
m =1 / 4
then use the slope intercept formula
y = 1/4x + 5 for your answer. we know b = 5 b/c thats where the line crosses the y axis.
y = x + 5 is the answer
Answer:
d. x ≥ 2 or x ≤ -2
Step-by-step explanation:
The domain is the set of all possible x-values that will make the function work.
For the function to work, the radicand cannot be negative.
x² - 4 ≥ 0
x² ≥ 4
x ≥ 2 -x ≥ 2
x ≤ -2
The domain is x ≥ 2 and x ≤ -2.
The graph of your function shows that ƒ(x) does not exist when -2 < x < 2.
Answer:
The college should offer 20 practical courses and 10 humanistic courses in order to maximize the revenue.
Step-by-step explanation:
a)
Let x and y be
<em>x= number of practical courses the college will offer</em>
<em>y= number of humanistic courses the college will offer</em>
we have the following inequalities
x ≥ 10
y ≥ 10
x+y = 30
The only points (x,y) that satisfy all this inequalities are (10,20) and (20,10) (see picture attached).
On the other hand, the revenues would be given by
R = 1,500x + 1,000y
The maximum of R is attained in (x,y) = (20,10) and is
R = 300,000 + 100,000 = 400,000
and the college should be offering 20 practical courses and 10 humanistic ones.
b)
If x = 21 then y must be 9, and then y does not satisfy y ≥ 10.
So you can only offer additional humanistic courses.
In n is an integer < 30
But if y=10+n then x must be 30-n and the revenue would be
R = 1,500(30-n) + 1,000(10+n) =
350,000 - 1,500n + 100,000+ 1,000n =
400,000 - 500n < 400,000
This result means in terms of offering additional courses, that is not worth doing it.
