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Ulleksa [173]
4 years ago
8

What is the correlation coefficient between the variables? Round to three decimal places. Enter your answer in the box. r≈ Age/Q

uiz Score 4/38 10/42 8/39 5/35 7 /42 9/45 6/40
Mathematics
1 answer:
mafiozo [28]4 years ago
6 0

The correct answer is 0.739 You are rounding to 3 decimal places not 4 :D

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Examine the right triangle. What is the length of the hypotenuse, c? <br> Answers are in the pic
Olenka [21]

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3 years ago
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5x23x2 use properties to find the sum or protuct
sertanlavr [38]

Answer:

230

Step-by-step explanation:

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3 years ago
How would I graph this 8x-5y=15?
FromTheMoon [43]
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3 years ago
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Oduvanchick [21]

Answer:

  see attached

Step-by-step explanation:

The Pythagorean theorem can be used to find the hypotenuse associated with each pair of legs. That tells you ...

  c² = a² +b² . . . . . legs a, b; hypotenuse c

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<h3>alternate form of Pythagorean theorem</h3>

For the purpose of this problem, it is convenient to consider a slightly different form of the equation.

For legs √a and √b, the hypotenuse √c is given by ...

  (√c)² = (√a)² +(√b)²

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That is ...

  legs √a, √b ⇒ hypotenuse √(a+b)

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<h3>application to this problem</h3>

Since the legs are (mostly) given in terms of square roots, the value under the radical for the hypotenuse is simply the sum of those:

legs: √1, √2 ⇒ hypotenuse √(1+2) = √3

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legs: √5, √3 ⇒ hypotenuse √(5+3) = √8

legs: √5, √1 ⇒ hypotenuse √(5+1) = √6

_____

<em>Additional comment</em>

You may not see the leg lengths given as square roots very often. This is a rather unusual set of problems for hypotenuse length.

6 0
2 years ago
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When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?
Radda [10]
The correct answer for this question is this one: "B. increase your scale values"

<span>When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by </span><em>increasing your scale values</em>
Hope this helps answer your question and have a nice day ahead.
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3 years ago
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