Answer:
There are 801 box seats and 9612 regular seats.
explanation:
Let the number of box seats be x,
Then the regular seats is 12x
The sum of seats equals to 10,413
<u>Solve:</u>
12x + x ➙ 10,413
13x ➙ 10413
x ➙ 801
There are 801 box seats.
<u>Find for regular seats:</u>
➙ 12(x)
➙ 12(801)
➙ 9612
There are 9612 regular seats.
Answer(s):
Exact Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3 2 3
Mixed Number Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3 2 3
Improper Fraction Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 11 3
Decimal Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3. ¯ 6
Hope this helps, have a nice day/night! :D
Answer:
w-2u-v
Step-by-step explanation:
Given are three vectors u, v and w.
In R^2 we treat first element as x coordinate and 2nd element as y coordinate.
Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.
b) 
We have to find the values of a and b
]
Equate the corresponding terms

Divide II equation by 2 to get

Eliminate a
-5 = 5b: b=-1
a=-2
Hence
w = 2u-v