Height of the kite is = 36 inches.
Width of the kite is = 30 inches
One of the ways to find the area is to draw a vertical line to break the kite into two equal triangles. Mark the base as 36 inches and height as 15 inches .
Now we will use the formula 
to find the area of each triangle. Then we will add both the areas to find the area of the kite.
Area of 1 triangle = 
= 270 square inches
Area of the 2nd triangle is also = 270 square inches
Hence, area of the kite = 270+270 = 540 square inches
Answer:
Step-by-step explanation:
There isn’t a picture its all black
Try to fix that lol
<span>From the message you sent me:
when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths
If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function
Why does this work? Initially, you start with 500 mL of air that you breathe in, so
. After the second breath, you have 12% of the original air left in your lungs, or
. After the third breath, you have
, and so on.
You can find the amount of original air left in your lungs after
breaths by solving for
explicitly. This isn't too hard:
and so on. The pattern is such that you arrive at
and so the amount of air remaining after
breaths is
which is a very small number close to zero.</span>
Answer:
26
Step-by-step explanation:
Use the Pythagorean Theorem: 
The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
![\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20%5Ctext%7BFrom%20the%20graph%2C%20%7D%20%5C%5C%20x1%5Ctext%7B%20%3D%201%2C%20y1%20%3D%201%7D%20%5C%5C%20x2%5Ctext%7B%20%3D%207%2C%20y2%20%3D%209%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%287-1%29%5E2%2B%289-1%29%5E2%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B6%5E2%2B8%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%2010%7D%20%5Cend%7Bgathered%7D)
Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters
