To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
The answer would have to be
D
2/5 (x-4)=2x answer is x= -1
Step-by-step explanation:
his mistake was that he didnt follow the rules of the order of operations and he multiplied 4 by 4 and just added the third power and the 6th power getting the wrong answer
hope this helps:) good luck
The answer is B
Volume of the cone: 63617.25
Volume of the cylinder: 891000
Hope this helps ;)
