All categories

3 years ago

What is the value of the geometric sequence for which a1=10 and r=0.5?

1 answer:

3 0

The formula for an infinite geometric sequence is the following:

$S_{∞}= \frac{a_{1}}{1-r}$

Just substitute the values of $a_{1}$ and r into the formula.

$S_{∞}=\frac{10}{1-0.5}$
$S_{∞}=\frac{10}{0.5}$
$S_{∞}= 20$

Therefore, the answer is 20.

You might be interested in

How do you solve this using substitution method 17x+7y=20 Y=20x-42

Nutka1998 [239]

Answer:

17 x + 7 y = 20

y =20x - 42

17 x + 7(20x - 42) = 20

17x + 140x - 294 = 20

157 x = 20 + 294

157x ÷ 157 = 314 ÷ 157

x = 2

y = 20x - 42 

y = 20 (2) - 42

y = 40 - 42

y = -2

there for x = 2 and y = -2 is the solution 

4 0

2 years ago

A farmer is comparing the number of eggs laid by two hens. The first hen laid 7 eggs per week for x weeks. The second hen laid 8

nikitadnepr [17]

Answer:

7x ≥ 8y

Step-by-step explanation:

The first hen laid 7 eggs per week for x weeks. 7x

The second hen laid 8 eggs per week for y weeks. 8y

The total number of eggs laid by the first hen was at least the total number of eggs laid by the second hen.

7x ≥ 8y

7 0

3 years ago

SOMEONE PLEASE ACTUALLY HELP ME!!!!

ser-zykov [4K]

Answer:

with what do u need help with?

4 0

3 years ago

Read 2 more answers

HELP, ASAP PLS. 24 POINTS.

Afina-wow [57]

Oh my......um you should get tutoring for that im not that smart

8 0

3 years ago

what effect does doubling the radius of a cone have on the volume of the cone if the height remains the same

Butoxors [25]

V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2

so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)

it is 4 times the old one

4 0

3 years ago